Answer:
the answer is 7 + 35v

Answer:

**Answer:**

7 + 35v

**Step-by-step explanation:**

7 × 1 + 5v × 7

**7 + 35v**

**Hope this helps and have a nice life d:**

) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station

anna needs at least $1000 to pay her bills this week.she has $250 in the bank and makes $15 an hour at her job.how many hours does she have to work thus week in order to pay her bills

Dilution ProblemSamantha needs 115 liters of a solution that has a concentration of 14 g/ml for the manufacture of computer parts. Samantha has an unlimited supply of a solution with a concentration of 21 g/ml.Using the Formula C1×V1 = C2×V2 to answer the following questionsRound answers to the nearest 10th.How many liters of 21 g/ml does Samantha need to equals the amount of soluble in the given solution?(Concentration times Volume = grams of soluble, like salt)

HELP QUICK BRAINLIEST IF CORRECT! Thanks!!

Integral rational trigonometric

anna needs at least $1000 to pay her bills this week.she has $250 in the bank and makes $15 an hour at her job.how many hours does she have to work thus week in order to pay her bills

Dilution ProblemSamantha needs 115 liters of a solution that has a concentration of 14 g/ml for the manufacture of computer parts. Samantha has an unlimited supply of a solution with a concentration of 21 g/ml.Using the Formula C1×V1 = C2×V2 to answer the following questionsRound answers to the nearest 10th.How many liters of 21 g/ml does Samantha need to equals the amount of soluble in the given solution?(Concentration times Volume = grams of soluble, like salt)

HELP QUICK BRAINLIEST IF CORRECT! Thanks!!

Integral rational trigonometric

In 1906, San Francisco felt the impact of an earthquake with a magnitude of 7.8. Many pundits claim that the worst is yet to come, with an earthquake 748,180 times as intense as the 1906 earthquake ready to hit San Francisco. If the pundits ability to predict such earthquakes were correct, what would be the magnitude of their claimed earthquake? Round your answer to the nearest tenth.

**Answer:**

The magnitude of the claimed earthquake would be 13.67.

**Step-by-step explanation:**

The 1906 earthquake had a intensity of A and a magnitude of 7.8.

S is going to have the same value, so i am going to write as 1. So:

**Many pundits claim that the worst is yet to come, with an earthquake 748,180 times as intense as the 1906 earthquake ready to hit San Francisco.**

So

So

The magnitude of the claimed earthquake would be 13.67.

**Answer:**

the answer is **32.8in.**

**Step-by-step explanation:**

(sin 22)/42 = (sin 24)/x

x = 45.60

sin 46 = x/45.60

x = 32.80

**32.8in.**

hope it helped :)

mark me brainliest!

**Answer:**

D

**Step-by-step explanation:**

if AB is congruent to AC that means both are 76 degrees so subtract that from the total degrees of a whole triangle which is 180 that gives you A which is 28.

Hope it helps :)

**➷** You can use this formula:

area = 1/2ab * sinC

Substitute the values in:

area = 1/2(17)(15) * sin(35)

Solve:

area = 73.13099

This can be rounded to give the answer of:

73.1 m^2

**➶ **Hope This Helps You!

**➶ **Good Luck (:

**➶ **Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ** ♡**

**Answer:**

15 rides

**Step-by-step explanation:**

Subtract $7 from $29.50

and then divide what you got ($22.50) from $1.50

b) What is the probability that the class hangs Wisconsin's flag on Monday, Michigan's flag on Tuesday, and California's flag on Wednesday.?

c) What is the probability that Wisconsin's flag will be hung at least two of the three days?

**Answer:**

**a.) P(x = X) = **

**b.) **

**c.) 0.00118**

**Step-by-step explanation:**

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

=

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

=

=

=

**= 0.00118**

The sample space for this experiment is all the possible combinations of flags from the 50 U.S. states for the three days. The probability of hanging Wisconsin's flag on Monday, Michigan's on Tuesday, and California's on Wednesday is 1/125,000. The probability of hanging Wisconsin's flag at least two of the three days is 294/125,000.

a) The sample space Ω for this experiment comprises of all possible combinations of flags from the 50 U.S. states for the three days. Hence, the total number of outcomes in the sample space Ω would be 50*50*50 = 125,000. Every outcome in this space is equally likely, so the probability measure P would assign a probability of 1/125,000 to each outcome.

b) As each day's choice is independent of the others and each state's flag is equally likely to be chosen, the **probability** that Wisconsin's flag is hung on Monday, Michigan's flag is hung on Tuesday, and California's flag is hung on Wednesday would be (1/50) * (1/50) * (1/50) = 1/125,000.

c) To find the **probability** that Wisconsin's flag will be hung at least two of the three days, we have to add the probabilities for the three situations where Wisconsin's flag is hung exactly twice plus the situation where Wisconsin's flag is hung all three days. The final probability would be [(3 * (1/50)² * (49/50)) + (1/50)³] = 294/125,000.

#SPJ3