x2 = 20

a.4.47

b. -3.97, 3.97

c. -10, 10

d. -4.47, 4.47

Answer:

**Answer: if using the quadratic formula it is D :) **

**hope this helps**

**Step-by-step explanation:**

PLEASE HELP!!!Aidan is 5.5 ft tall and casts a shadow that is 9 ft long. He notices that a nearby tower casts a shadow that is 305 ft long.What is the height of the tower (h)?

A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What is the length of AB? (3) What are the coordinates of the mid point of AB?(4) What is the slope of a line perpendicular to AB ?

What is the next number in the sequence? 3….9….27….81….A) 162B) 180C)243D) 270

Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning. After 9 hours of burning, a candle has a height of 25.4 centimeters. After 23 hours of burning, its height is 19.8 centimeters. What is the height of the candle after 22 hours?

Divide and simplify to the form a+bi. 5+6i 5+6i 6+ i (Simplify your answer. Type an integer or a fraction. Type your answer in the form a+bi.)

A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What is the length of AB? (3) What are the coordinates of the mid point of AB?(4) What is the slope of a line perpendicular to AB ?

What is the next number in the sequence? 3….9….27….81….A) 162B) 180C)243D) 270

Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning. After 9 hours of burning, a candle has a height of 25.4 centimeters. After 23 hours of burning, its height is 19.8 centimeters. What is the height of the candle after 22 hours?

Divide and simplify to the form a+bi. 5+6i 5+6i 6+ i (Simplify your answer. Type an integer or a fraction. Type your answer in the form a+bi.)

For ten weeks, City A received less rainfall, on average, than City B.

The range between the maximum and minimum values for City B is greater than the range between maximum and minimum values for City A.

During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

The median for City A is less than the median for City B.

Answer:

During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

Step-by-step explanation:

Given the data :

City A :

Reordered data:

0, 0.2, 0.2, 0.3, 0.4, 1, 1.3, 1.5, 2.5, 3

City B :

Reordered data:

0, 0, 0.1, 0.1, 0.2, 0.3, 0.4, 1, 1, 1

Using a calculator :

Mean Rainfall for City A = 1.04

Mean rainfall for city B = 0.41

Range : maximum - minimum

City A = 3 - 0 = 3

City B = 1 - 0 = 1

Mode (most occurring) :

City A = 0.2

City B = 1

Median :

City A = 0.7

City B = 0.25

The only true conclusion in the options given that can be drawn from the data is that ;During the 10 wk period, the rainfall amount recorded most often for City B was 1 in.

**Answer:**

the Answer is C.

**Step-by-step explanation:**

**I just took the test**

**Step-by-step explanation:**

**Let****the ****two ****numbers ****be ****x ****and ****y**

**By ****the ****question **

**x ****+****y ****=****8****7****.****.****.****.****.****equation ****(****I) **

**x ****-****y ****=****6****5****.****.****.****.****.****.****equation ****(****II) **

**Now ****adding ****both ****equations ****we ****get **

**2x ****=****1****5****2**

**x ****=****1****5****2****/****2**

**Therefore ****x ****=****7****6**

**Putting ****x ****=****7****6****in ****equation ****i**

**7****6****+****y ****=****8****7**

**y ****=****8****7****-****7****6**

**Therefore ****y ****=****1****1**

**The ****two ****numbers ****are ****7****6****and ****1****1****.**

**Hope ****it ****helps ****:****)**

**Answer:**

11, 76

**Step-by-step explanation:**

Let the two numbers be x and y.

According to the given conditions:

x + y = 87.....(1)

x - y = 65....(2)

Adding equations (1) & (2)

x + y = 87

x - y = 65

__________

2x = 152

x = 152/2

x = 76

Plug x = 76 in equation (1)

76 + y = 87

y = 87 - 76

y = 11

Thus the two numbers are 11 and 76.

answer with coding and answer is attached in word file below

The **doublePennies() function **is an illustration of a **recursive function **in Java

The** base case **of the **doublePennies() function **is that:

When the **number of days **is 0, then the **total available pennies **is the same as the **total number of pennies.**

The **algorithm **of the above highlight is:

if numDays equals 0 then

totalPennies = numPennies

Using the above **algorithm**, the complete **base case **is:

if(numDays == 0){

totalPennies = numPennies;

}

Read more about **Java programs** at:

**Answer:**

3/8

**Step-by-step explanation:**

add 5+1+3=9

and there is 3 cheese pizza so its 3 over 8.

**Answer:**

3/9

**Step-by-step explanation:**

Let the two numbers be x and y

Their sum is 20, so we can write

x + y = 20

Their difference is 14, so we can write:

x- y = 14

Adding the two equations, we get:

2x = 34

x = 17

Using the value of x, in first equation, we get:

17 + y = 20

so,

y = 3

Thus the two numbers are 17 and 3.

**So, option a is the correct answer**

Their sum is 20, so we can write

x + y = 20

Their difference is 14, so we can write:

x- y = 14

Adding the two equations, we get:

2x = 34

x = 17

Using the value of x, in first equation, we get:

17 + y = 20

so,

y = 3

Thus the two numbers are 17 and 3.

For this case we have the following system of equations:

x + y = 20

x-y = 14

Where,

x: real number

y: real number

Solving the system we have:

x = 17

y = 3

Therefore, the numbers are:

17 and 3

**Answer:**

**17 and 3**

**option 1**

x + y = 20

x-y = 14

Where,

x: real number

y: real number

Solving the system we have:

x = 17

y = 3

Therefore, the numbers are:

17 and 3

multi-step equations

**Answer:**

y = 2

**Step-by-step explanation:**

This equation can be solved three steps, classifying it as a multi-step equation.

To solve, you need to get the constants on one side and the variables on the other and then isolate the variable. These steps are illustrated below.

3y + 2 = 2y + 4 **Subtract 2y from both sides of the equation**.

y + 2 = 4 **Subtract 2 from both sides of the equation**.

**y = 2**