a Pontiac trans-am, initially at rest accelerates at a constant rate of 4.0 m/s squared for six seconds how fast will the car be traveling a T equals six seconds

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Answer 1
Answer: use formula: a= Vf-Vi/t
rearrange: Vf=at
solve: Vf= 4.0m/s squared x 6s
          Vf = 24 m/s --> sigdigs
          Vf = 2.4 x 10^1 m/s


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An ionic bond form when atoms

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between two ions of opposite charges. In ionic bonding, electrons transfer from one atom to another.

Describe what happens if you are riding a skateboard and hit something like a curb with the front wheels.

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If you are riding a skateboard and hit something like a curb with the front wheels then the skateboard would stop due to the friction offered by the club but your body would fall forward due to the effect of that inertia.

What is Newton's first law?

According to Newton's first law, until pushed to alter its condition by the intervention of an external force,

Every object will continue to be at rest or in uniform motion along a single direction until/unless some external force is applied.

When the front wheels of a skateboard collide with something like a curb, then the skateboard will halt because of the friction created by the object, but your body will fall forward as a result of the inertia.

Learn more about Newton's First Law here, refer to the link;

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Your body will keep moving forward and fly off your skateboard since the curb only stops the board, not yourself.

a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

The expression for the bullet's speed vbullet is v=\sqrt{(2\mu_k (m+M)gd)/(m)} and  the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A  bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

K_i = (1)/(2)mv^2

where

m is the mass of the bullet  

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

F=\mu_k (m+M) g

where

\mu_k is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

W=-Fd = -\mu_k (m+M)g d

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

W=K_f - K_i = -K_i

And so

-\mu_k (m+M) g d = -(1)/(2)mv^2

By solving for v, the solution for the bullet speed:

-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, \mu_k = 0.20

the acceleration of gravity, g = 9.8 m/s^2

By substituting, we got

v=\sqrt{(2 (0.20) (0.009 kg+12 kg)(9.8 m/s^2)(0.054 m))/(0.009 kg)}=16.8 m/s

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uk=2m*the normal force
the distance d is needed only if you were asked about work

A girl with a mass of 40 kg is swinging from a rope with a length of 2.5 m. What is the frequency of her swinging?

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For a pendulum with a massless rope 'L' meters long, swinging through
a small arc, the period of the swing is

                     2 π √(L/g)  seconds .

and it doesn't depend on the mass of the thing on the end of the rope ...
that could be a pebble or a bus.

For the girl on the 2.5-m rope,

                   Period = (2 π) √(2.5 / 9.8) =  3.17 seconds

Frequency = 1 / period = about  0.315 Hz .


If a girl with a mass of 40 kg is swinging from a rope with a length of 2.5 m , then the frequency of her swinging is 0.32 Hz

Further explanation

Simple Harmonic Motion is a motion where the magnitude of acceleration is directly proportional to the magnitude of the displacement but in the opposite direction.

The pulled and then released spring is one of the examples of Simple Harmonic Motion. We can use the following formula to find the period of this spring.

\large { \boxed {T = 2 \pi\sqrt{(m)/(k)} } }

T = Periode of Spring ( second )

m = Load Mass ( kg )

k = Spring Constant ( N / m )

The pendulum which moves back and forth is also an example of Simple Harmonic Motion. We can use the following formula to find the period of this pendulum.

\large { \boxed {T = 2 \pi\sqrt{(L)/(g)} } }

T = Periode of Pendulum ( second )

L = Length of Pendulum ( kg )

g = Gravitational Acceleration ( m/s² )

Let us now tackle the problem !

Given:

Mass of A Girl = m = 40 kg

Length of Rope = L = 2.5 m

Gravitational Acceleration = g = 10 m/s²

Unknown:

Frequency of Swinging = f = ?

Solution:

Recall the formula for calculating period as mentioned above.

T = 2 \pi\sqrt{(L)/(g)}

T = 2 \pi\sqrt{(2.5)/(10)}

T = 2 \pi\sqrt{(1)/(4)}

T = 2 \pi (1)/(2)

T = \pi ~ seconds

T \approx 3.1 ~ seconds

Finally, we can calculate the magnitude of frequency with the following formula.

f = (1)/(T)

f = (1)/(\pi) ~ Hz

f \approx 0.32 ~ Hz

Learn more

Answer details

Grade: High School

Subject: Physics

Chapter: Simple Harmonic Motion

Keywords: Simple , Harmonic , Motion , Pendulum , Spring , Period , Frequency

True or false one of the benefits of using an exercise ball is generally involves the core muscles?

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the answer is true improve core stability
This is true in many cases, but not all. There are exercises in which you simply raise and lower an exercise ball over your head (kind of like weight lifting), but whenever the ball is in front of you and you reach out at all with your arms, that is a core workout. 

Select all that apply.A longitudinal wave is characterized by _____.
peaks compressions dips rarefactions

Answers

A longitudinal wave ischaracterized by rarefactions. A longitudinal wave is a wave motion wherein theparticles in the wave medium are displaced parallel to the advancing wave. When motionis detected from the source, the particle next to it vibrates from its rest positionand a progressive change in phase vibration is observed at each particle withinthat wave. The result is that the energy is transported from one region to theother. These combined motions result in the movement of alternating regions of rarefactionin the direction of transport of energy.       
It's characterized by both compression and rarefaction.

(the compression in front of the waves induces a rarefaction behind the wave)