Answer:
so F(m) because F dollars for every mph over the speed limit

so 40 dollar speeding fine so +40

10 dollars for every mile over and m=miles over so put them all toghether and get

F(m)=10m+40

1.

so if you were going 78 mph

to find the mph over you would do 78-70=8mph over so put in 8 for m and get

F(8)=10(8)+40=80+40=$120 fine for going at 78 mph

so 40 dollar speeding fine so +40

10 dollars for every mile over and m=miles over so put them all toghether and get

F(m)=10m+40

1.

so if you were going 78 mph

to find the mph over you would do 78-70=8mph over so put in 8 for m and get

F(8)=10(8)+40=80+40=$120 fine for going at 78 mph

Can someone please help me

System of equations2x+4y=8X=3y-6

Which of the following is not equivalent to the formula d = rt?

Which equation does not have the same solution as the others?x/4 = 2,x - 9 = 17,x + 12 = 20,2x = 16.

Can you help with the question

System of equations2x+4y=8X=3y-6

Which of the following is not equivalent to the formula d = rt?

Which equation does not have the same solution as the others?x/4 = 2,x - 9 = 17,x + 12 = 20,2x = 16.

Can you help with the question

**Answer:**

x=8 and x=9

**Step-by-step explanation:**

The given equation is:

On solving this equation, we get

⇒

Squaring on both sides, we get

⇒

⇒

⇒

⇒

⇒

**Thus, the solution of the above equations are x= 8 and x=9.**

I"m guessing you mean

add 5 to both sides

square both sides

x+9=x²+18x+81

minus x+9 both sides

0=x²+17x+72

factor

what 2 numbres multiply to get 72 and add to get 17?

8 and 9

0=(x+8)(x+9)

set to zer

0=x+8

x=-8

x+9=0

x=-9

test each

1-5=-4

-4=-4

true

-5=-5

true

the solutions are x=-9 and -8

add 5 to both sides

square both sides

x+9=x²+18x+81

minus x+9 both sides

0=x²+17x+72

factor

what 2 numbres multiply to get 72 and add to get 17?

8 and 9

0=(x+8)(x+9)

set to zer

0=x+8

x=-8

x+9=0

x=-9

test each

1-5=-4

-4=-4

true

-5=-5

true

the solutions are x=-9 and -8

Simplify the expression.

(−34p)^3

**Answer:**

**I hope this is the answer you’re looking for **

-39304p^3

**Step-by-step explanation:**

nickels is 0,05 of dolar - n

dimes is 0,1 o dolar -d

quarters is 0,25 of dolar -q

dimes =2nickels

d=2n

quarters=2dimes

q=2d=4n

12,5=n(0,05)+2n(0,1)+4n(0,25)

12,5=0,05n+0,2n+n

12,5=1,25n

n=10

q=4n=40

There are 40 quarters

dimes is 0,1 o dolar -d

quarters is 0,25 of dolar -q

dimes =2nickels

d=2n

quarters=2dimes

q=2d=4n

12,5=n(0,05)+2n(0,1)+4n(0,25)

12,5=0,05n+0,2n+n

12,5=1,25n

n=10

q=4n=40

There are 40 quarters

**Answer:**

I think your correct

**Step-by-step explanation:**

the answer you picked looks like an image on my notes

sorry if its not

The compound **inequalities **for each number line is 18: −1≤x≤4 19: −3<x≤2 20: x<0 or (1≤x≤3) 21: (−4<x≤−6) or (−3<x≤0) 22: (3≤x<1) or (6<x<7) 23: (−3≤x≤−4) or (0<x<2).

let's break down the compound inequalities for each situation step by step:

18:

−1≤x≤4 (closed on both ends)

The **notation **≤ means "less than or equal to," so

−1≤x indicates that

x can be equal to or greater than -1.

Likewise,

x≤4 means that

x can be equal to or less than 4.

**Combining **both inequalities, we have

−1≤x≤4, indicating that

x can take any value between -1 and 4, including -1 and 4.

19:

−3<x≤2 (open on the left end, closed on the right end)

The **notation **< means "less than," so −3<x indicates that

x must be greater than -3 but not equal to -3.

x≤2 means that

x can be equal to or less than 2.

Combining both inequalities, we have

−3<x≤2, indicating that x can take any **value greater** than -3 and up to and including 2. It's open at -3 but closed at 2.

20: x<0 or (1≤x≤3) (open on the left end, closed on the right end, with a gap between 0 and 1)

x<0 indicates that x must be less than 0.

(1≤x≤3) indicates that x can be equal to or greater than 1 and equal to or less than 3.

Combining these two inequalities with "or," we have

x<0 or

1≤x≤3, indicating that x can be less than 0 or take any value between 1 and 3, including 1 and 3.

21:

(−4<x≤−6) or

(−3<x≤0) (open on both ends with a gap between -3 and -4)

(−4<x≤−6) indicates that x must be **greater than** -4 but not equal to -4, and it can be equal to or less than -6.

(−3<x≤0) indicates that x must be greater than -3 but not equal to -3, and it can be equal to or less than 0.

Combining these two inequalities with "or," we have

(−4<x≤−6) or

(−3<x≤0), indicating that

x can take any value greater than -4 and up to -6, or greater than -3 and up to 0.

22:

(3≤x<1) or

(6<x<7) (closed on the left end, open on the right end, with a gap between 1 and 6)

(3≤x<1) indicates that x can be equal to or greater than 3 and less than 1.

(6<x<7) indicates that x must be greater than 6 and less than 7.

Combining these two inequalities with "or," we have

(3≤x<1) or (6<x<7), indicating that x can take any value equal to or **greater than** 3 and less than 1, or greater than 6 and less than 7.

23:

(−3≤x≤−4) or

(0<x<2) (closed on the left end, open on the right end, with a gap between -4 and 0)

(−3≤x≤−4) indicates that x can be equal to or greater than -3 and equal to or less than -4.

(0<x<2) indicates that

x must be greater than 0 but less than 2.

Combining these two inequalities with "or," we have

(−3≤x≤−4) or

(0<x<2), indicating that x can take any value equal to or greater than -3 and equal to or less than -4, or greater than 0 and less than 2.

These compound **inequalities **describe the ranges of values for x in each given situation on the number line.

To know more about **inequality**:

#SPJ3

**Answer:18-1 closed right 5**

**19-3 open right5**

**20 0 open left 1 3 closed right 1**

**21 -4 open left 2 -3 open right 3**

**22 3 close left 2 6 open right 1**

**23-3 open left 1 0 open right 2**

**Step-by-step explanation:**

The answer is A. informed decisions.

I hope this helps...

I hope this helps...

**Answer:**

The answer is A.