Answer:
90

15 is 5/9 of 27... 90 is 5/9 of 162

15 is 5/9 of 27... 90 is 5/9 of 162

Answer:
games lost : games played --> games lost/games played

12/15 =?/162

cross multiply and divide. --> 12 x 162/15 =129.6

that means, they will lose about 130 games out of 162. therefore they will win about 32 games.

12/15 =?/162

cross multiply and divide. --> 12 x 162/15 =129.6

that means, they will lose about 130 games out of 162. therefore they will win about 32 games.

A math book comprises of 2 sections: arithmetic and geometry in the ratio 5:3. How much of each type of content will be needed to make a book of 480 pages?

NEED HELP WITH DIS ASAPPPP !!!

Write in miles per hour. Round to the nearest tenth.3.7 mi/min

Prove that

Ryan created the two-way table below to describe his scoring in his soccer team’s wins and losses last season.Ryan’s Scoring in Wins and LossesTeam WonTeam LostRyan Scored64Ryan Did Not Score911In what percentage of the team’s wins did Ryan score a goal?20%40%60%67%

NEED HELP WITH DIS ASAPPPP !!!

Write in miles per hour. Round to the nearest tenth.3.7 mi/min

Prove that

Ryan created the two-way table below to describe his scoring in his soccer team’s wins and losses last season.Ryan’s Scoring in Wins and LossesTeam WonTeam LostRyan Scored64Ryan Did Not Score911In what percentage of the team’s wins did Ryan score a goal?20%40%60%67%

From the given data:

Number of items | Probability of being purchased | Average amount spent

--------------------------------------------------------------------------------------------------

2 | 0.35 | $12

3 | 0.17 | $20

4 | 0.33 | $28

5 or more | 0.15 | $36

In a sample space of 100 items being purchased, in a day:

For 2 items: 35 (12) = 420

For 3 items: 17 (20) = 340

For 4 items: 33 (28) = 924

For 5 or more items: 15 (36) = 540

If this sample trend would go on the for the next two weeks, then the transaction with 4 items would most likely bring in the most income during the said transaction period.

Number of items | Probability of being purchased | Average amount spent

--------------------------------------------------------------------------------------------------

2 | 0.35 | $12

3 | 0.17 | $20

4 | 0.33 | $28

5 or more | 0.15 | $36

In a sample space of 100 items being purchased, in a day:

For 2 items: 35 (12) = 420

For 3 items: 17 (20) = 340

For 4 items: 33 (28) = 924

For 5 or more items: 15 (36) = 540

If this sample trend would go on the for the next two weeks, then the transaction with 4 items would most likely bring in the most income during the said transaction period.

**Answer: **

Based on the data provided, transactions with **4 ** items are likely to bring in the most income during the next two-week transaction period.

(x + 2)¹⁰

Would take the terms in reducing powers of x, and increasing powers of 2.

1st term = ¹⁰C₀ x¹⁰(2)⁰ = x¹⁰

Second term = ¹⁰C₁ x¹⁰⁻¹(2)¹ = ¹⁰C₁ x⁹(2)¹

Third term = ¹⁰C₂ x¹⁰⁻²(2)² = ¹⁰C₂ x⁸(2)²

Fourth term = ¹⁰C₃ x¹⁰⁻³(2)³ = ¹⁰C₃ x⁷(2)³

So we shall now simplify the fourth term which is = ¹⁰C₃ x⁷(2)³

ⁿCr = n! /( r!(n -r)! )

¹⁰C₃ = 10! /( 3!(10 -3)! ) = 10! / (3!*7!) = (10 *9 * 8* 7!) / (3!*7!)

= 10*9*8 / 3! = (10*9*8) / (3*2*1) = 120

4th term = ¹⁰C₃ x⁷(2)³ = 120 *x⁷*(2)³ = 120*2³*x⁷

= 120*8x⁷

= 960x⁷

So the fourth term in reducing powers of x = 960x⁷

I hope this helped.

Would take the terms in reducing powers of x, and increasing powers of 2.

1st term = ¹⁰C₀ x¹⁰(2)⁰ = x¹⁰

Second term = ¹⁰C₁ x¹⁰⁻¹(2)¹ = ¹⁰C₁ x⁹(2)¹

Third term = ¹⁰C₂ x¹⁰⁻²(2)² = ¹⁰C₂ x⁸(2)²

Fourth term = ¹⁰C₃ x¹⁰⁻³(2)³ = ¹⁰C₃ x⁷(2)³

So we shall now simplify the fourth term which is = ¹⁰C₃ x⁷(2)³

ⁿCr = n! /( r!(n -r)! )

¹⁰C₃ = 10! /( 3!(10 -3)! ) = 10! / (3!*7!) = (10 *9 * 8* 7!) / (3!*7!)

= 10*9*8 / 3! = (10*9*8) / (3*2*1) = 120

4th term = ¹⁰C₃ x⁷(2)³ = 120 *x⁷*(2)³ = 120*2³*x⁷

= 120*8x⁷

= 960x⁷

So the fourth term in reducing powers of x = 960x⁷

I hope this helped.

(Not drawn accurately)

**Answer:**

1782

**Step-by-step explanation:**

I got this by multiplying the sides and dividing the shapes and sizes to the power of pie then added a +c and got 172

Answer:

70.42

Step-by-step explanation:

**Answer:**

**f^-1(x) = 1/(5x - 3) **(See explanation for alternate answer)

**Step-by-step explanation:**

Assuming you meant f(x) = 1/(5x) + 3/5

y = 1/(5x) + 3/5

(I like to substitute x and y early on)

x = 1/(5y) + 3/5

5x = 1/y + 3

1/y = 5x - 3

**f^-1(x) = 1/(5x - 3)**

Assuming you meant f(x) = 1x/5 + 3/5

y = 1x/5 + 3/5

x = 1y/5 + 3/5

5x = y + 3

**f^-1(x) = 5x - 3**

It must be larger than 25. The 3rd side of a triangle must always be greater than the sum of th other 2

**Answer: The required co-ordinates of he point K are (9.2, 7). **

**Step-by-step explanation: **Given that the the endpoint of MP are M(2,1) and P(14,10) and the point K partitions MP in the ratio of MK : KP = 3 : 2.

We are to find **the co-ordinates of point K.**

We know that

the **co-ordinates of a point that divides the line joining the points (a, b) and (c, d) in the ratio m : n** are given by

For the given division,** m : n = 3 : 2.**

**Therefore, the co-ordinates of the point K are**

**Thus, the required co-ordinates of the point K are (9.2, 7). **

2(2,1)(14,10)

(4,2) - (14,10)= (-10, -8)

The coordinates of K are (-10, -8).